![]() (Vote for please, I'm just illustrating how to clearly explain - I hope - what you want to achieve, sample data, etc). WHERE string_a LIKE ANY (SELECT '%'||candidate_str||'%' FROM tableB) If so, shamelessly stealing excellent suggestion, you would use: SELECT string_a bork doesn't match any substring so it is not found. There is no need to show the substring(s) that matched. 1 Answer Sorted by: 27 Assuming that 2015mmdd actually means some kind of 'date', so that the real data contains e.g. I want the result set: the manual is greatīecause the manual is great has man and great in it and because chicken chicken chicken has chicken in it. The string argument represents the string for which the substring is to be searched. Syntax: POSITION (substring in string) Let’s analyze the above syntax: The substring argument is the string that is to be located. Some of them are used internally to implement the SQL -standard string functions listed in Table 9-5. ('the manual is great'), ('Chicken chicken chicken'), ('bork') The PostgreSQL POSITION () function returns the location of a substring in a string. SQL String Functions and Operators Additional string manipulation functions are available and are listed in Table 9-6. Given: CREATE TABLE tableA (string_a text) The overhead of creating the rows, and the running the aggregate is just simply too high. ![]() The chosen answer was shown to be massively slower than an adapted version of regexpreplace (). SELECT FirstName, BITLENGTH ( FirstName) from Person Output: 3. 4 Answers Sorted by: 13 I would highly suggest checking out this answer I posted to 'How do you count the occurrences of an anchored string using PostgreSQL'. ASCII () works for characters with numeric values from 0 to 255. The following table details the important string functions ASCII (str) Returns the numeric value of the leftmost character of the string str. BITLENGTH (str) Returns the length of the string str in bits. PostgreSQL string functions are used primarily for string manipulation. SELECT FirstName, ASCII ( FirstName) from Person Output: 2. Sn is a substring of Sa.Ī simple example to show what I mean (hint, hint): ASCII (str) Returns the ASCII value of the leftmost character of the string str. Sn from table B to find out if any of the other strings in S1. The POSITION() function returns an integer that represents the location of the substring within the string. The string argument is the string for which the substring is searched. I'm going to take a wild stab in the dark and assume you mean that you want to match a string Sa from table A against one or more other strings S1. The substring argument is the string that you want to locate. ![]() How to find substring using results of subquery?ĬONSTRAINT uchastki_pkey PRIMARY KEY (fid),ĬONSTRAINT enforce_dims_the_geom CHECK (st_ndims(the_geom) = 2) In field test.str i have strings like 66:07:21 01 001 in uchastki.kadnum 66:07:21 01 001:27. Use the position () Function to SELECT if String Contains a Substring Match in PostgreSQL. I have a table and i want to find a string in one row (character varying datatype) of this table using substring (character varying datatype) returned by subquery: SELECT uchastki.kadnumīut get a error ERROR: more than one row returned by a subquery used as an expression
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